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132155034157 is a prime number
BaseRepresentation
bin111101100010100001…
…1011100101000101101
3110122010010000022201201
41323011003130220231
54131123142043112
6140413341005501
712355632153526
oct1730503345055
9418103008651
10132155034157
11510570871a3
1221742553891
13c6014c1283
14657979d84d
15368714c257
hex1ec50dca2d

132155034157 has 2 divisors, whose sum is σ = 132155034158. Its totient is φ = 132155034156.

The previous prime is 132155034119. The next prime is 132155034161. The reversal of 132155034157 is 751430551231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 129172672836 + 2982361321 = 359406^2 + 54611^2 .

It is a cyclic number.

It is not a de Polignac number, because 132155034157 - 231 = 130007550509 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132155034257) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66077517078 + 66077517079.

It is an arithmetic number, because the mean of its divisors is an integer number (66077517079).

Almost surely, 2132155034157 is an apocalyptic number.

It is an amenable number.

132155034157 is a deficient number, since it is larger than the sum of its proper divisors (1).

132155034157 is an equidigital number, since it uses as much as digits as its factorization.

132155034157 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 63000, while the sum is 37.

Adding to 132155034157 its reverse (751430551231), we get a palindrome (883585585388).

The spelling of 132155034157 in words is "one hundred thirty-two billion, one hundred fifty-five million, thirty-four thousand, one hundred fifty-seven".