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132155323515497 is a prime number
BaseRepresentation
bin11110000011000111001111…
…000111010000001001101001
3122022220220222201110021000002
4132003013033013100021221
5114310213100304443442
61145023152324552345
736556623054255242
oct3603071707201151
9568826881407002
10132155323515497
113912183792a147
12129a47065526b5
135898269269979
14248c4cd435cc9
1510429e36b3732
hex7831cf1d0269

132155323515497 has 2 divisors, whose sum is σ = 132155323515498. Its totient is φ = 132155323515496.

The previous prime is 132155323515493. The next prime is 132155323515539. The reversal of 132155323515497 is 794515323551231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 120889607190361 + 11265716325136 = 10994981^2 + 3356444^2 .

It is an emirp because it is prime and its reverse (794515323551231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 132155323515497 - 22 = 132155323515493 is a prime.

It is not a weakly prime, because it can be changed into another prime (132155323515491) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66077661757748 + 66077661757749.

It is an arithmetic number, because the mean of its divisors is an integer number (66077661757749).

Almost surely, 2132155323515497 is an apocalyptic number.

It is an amenable number.

132155323515497 is a deficient number, since it is larger than the sum of its proper divisors (1).

132155323515497 is an equidigital number, since it uses as much as digits as its factorization.

132155323515497 is an evil number, because the sum of its binary digits is even.

The product of its digits is 17010000, while the sum is 56.

The spelling of 132155323515497 in words is "one hundred thirty-two trillion, one hundred fifty-five billion, three hundred twenty-three million, five hundred fifteen thousand, four hundred ninety-seven".