Base | Representation |
---|---|
bin | 11110000011000111001111… |
… | …000111010000001010010011 |
3 | 122022220220222201110021001122 |
4 | 132003013033013100022103 |
5 | 114310213100304444124 |
6 | 1145023152324552455 |
7 | 36556623054255332 |
oct | 3603071707201223 |
9 | 568826881407048 |
10 | 132155323515539 |
11 | 3912183792a185 |
12 | 129a470655272b |
13 | 58982692699ac |
14 | 248c4cd435d19 |
15 | 10429e36b375e |
hex | 7831cf1d0293 |
132155323515539 has 2 divisors, whose sum is σ = 132155323515540. Its totient is φ = 132155323515538.
The previous prime is 132155323515497. The next prime is 132155323515541. The reversal of 132155323515539 is 935515323551231.
It is a strong prime.
It is an emirp because it is prime and its reverse (935515323551231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 132155323515539 - 232 = 132151028548243 is a prime.
Together with 132155323515541, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (132155323535539) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66077661757769 + 66077661757770.
It is an arithmetic number, because the mean of its divisors is an integer number (66077661757770).
Almost surely, 2132155323515539 is an apocalyptic number.
132155323515539 is a deficient number, since it is larger than the sum of its proper divisors (1).
132155323515539 is an equidigital number, since it uses as much as digits as its factorization.
132155323515539 is an evil number, because the sum of its binary digits is even.
The product of its digits is 9112500, while the sum is 53.
The spelling of 132155323515539 in words is "one hundred thirty-two trillion, one hundred fifty-five billion, three hundred twenty-three million, five hundred fifteen thousand, five hundred thirty-nine".
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