Base | Representation |
---|---|
bin | 11110000011000111001111… |
… | …101100101000000000010010 |
3 | 122022220221000101220000000011 |
4 | 132003013033230220000102 |
5 | 114310213110312000110 |
6 | 1145023153314545134 |
7 | 36556623233451103 |
oct | 3603071754500022 |
9 | 568827011800004 |
10 | 132155333312530 |
11 | 39121842410870 |
12 | 129a47098981aa |
13 | 589826b2ba028 |
14 | 248c4d08663aa |
15 | 10429e449b48a |
hex | 7831cfb28012 |
132155333312530 has 32 divisors (see below), whose sum is σ = 259621024443840. Its totient is φ = 48035002192320.
The previous prime is 132155333312521. The next prime is 132155333312539. The reversal of 132155333312530 is 35213333551231.
It is an interprime number because it is at equal distance from previous prime (132155333312521) and next prime (132155333312539).
It is not an unprimeable number, because it can be changed into a prime (132155333312539) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 268285920 + ... + 268778059.
It is an arithmetic number, because the mean of its divisors is an integer number (8113157013870).
Almost surely, 2132155333312530 is an apocalyptic number.
132155333312530 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
132155333312530 is a deficient number, since it is larger than the sum of its proper divisors (127465691131310).
132155333312530 is a wasteful number, since it uses less digits than its factorization.
132155333312530 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 537066234.
The product of its (nonzero) digits is 364500, while the sum is 40.
Adding to 132155333312530 its reverse (35213333551231), we get a palindrome (167368666863761).
The spelling of 132155333312530 in words is "one hundred thirty-two trillion, one hundred fifty-five billion, three hundred thirty-three million, three hundred twelve thousand, five hundred thirty".
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