Base | Representation |
---|---|
bin | 11110000011000111111110… |
… | …110101101001001110101111 |
3 | 122022221000001112002112212212 |
4 | 132003013332311221032233 |
5 | 114310221220244042444 |
6 | 1145023404010321035 |
7 | 36556651646106005 |
oct | 3603077665511657 |
9 | 568830045075785 |
10 | 132156124205999 |
11 | 391221088a1833 |
12 | 129a48aa72917b |
13 | 5898366101c2a |
14 | 248c567900a75 |
15 | 1042a3db2519e |
hex | 7831fed693af |
132156124205999 has 2 divisors, whose sum is σ = 132156124206000. Its totient is φ = 132156124205998.
The previous prime is 132156124205981. The next prime is 132156124206053. The reversal of 132156124205999 is 999502421651231.
It is a weak prime.
It is an emirp because it is prime and its reverse (999502421651231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 132156124205999 - 240 = 131056612578223 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132156124205929) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66078062102999 + 66078062103000.
It is an arithmetic number, because the mean of its divisors is an integer number (66078062103000).
Almost surely, 2132156124205999 is an apocalyptic number.
132156124205999 is a deficient number, since it is larger than the sum of its proper divisors (1).
132156124205999 is an equidigital number, since it uses as much as digits as its factorization.
132156124205999 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10497600, while the sum is 59.
The spelling of 132156124205999 in words is "one hundred thirty-two trillion, one hundred fifty-six billion, one hundred twenty-four million, two hundred five thousand, nine hundred ninety-nine".
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