Base | Representation |
---|---|
bin | 1100000001010010011011… |
… | …1111010011001001010010 |
3 | 1201210110111110211111212222 |
4 | 3000110212333103021102 |
5 | 3213013404213404430 |
6 | 44035245301021042 |
7 | 2532562311451262 |
oct | 300244677231122 |
9 | 51713443744788 |
10 | 13216268497490 |
11 | 4235a96023943 |
12 | 15954996b4782 |
13 | 74b39a57b766 |
14 | 3399569ab7a2 |
15 | 17dbbae8b9e5 |
hex | c0526fd3252 |
13216268497490 has 32 divisors (see below), whose sum is σ = 23918416758720. Its totient is φ = 5257845432000.
The previous prime is 13216268497477. The next prime is 13216268497493. The reversal of 13216268497490 is 9479486261231.
It is a super-3 number, since 3×132162684974903 (a number of 40 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (13216268497493) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 931940 + ... + 5225040.
It is an arithmetic number, because the mean of its divisors is an integer number (747450523710).
Almost surely, 213216268497490 is an apocalyptic number.
13216268497490 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13216268497490 is a deficient number, since it is larger than the sum of its proper divisors (10702148261230).
13216268497490 is a wasteful number, since it uses less digits than its factorization.
13216268497490 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4294778.
The product of its (nonzero) digits is 31352832, while the sum is 62.
The spelling of 13216268497490 in words is "thirteen trillion, two hundred sixteen billion, two hundred sixty-eight million, four hundred ninety-seven thousand, four hundred ninety".
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