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132174050413 is a prime number
BaseRepresentation
bin111101100011000101…
…1111111010001101101
3110122011102210110010111
41323012023333101231
54131143024103123
6140415300340021
712356252614516
oct1730613772155
9418142713114
10132174050413
1151066895409
12217489a4611
13c60541b9b2
14657c10da0d
153688b5690d
hex1ec62ff46d

132174050413 has 2 divisors, whose sum is σ = 132174050414. Its totient is φ = 132174050412.

The previous prime is 132174050341. The next prime is 132174050423. The reversal of 132174050413 is 314050471231.

Together with previous prime (132174050341) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 125643309444 + 6530740969 = 354462^2 + 80813^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132174050413 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132174050423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66087025206 + 66087025207.

It is an arithmetic number, because the mean of its divisors is an integer number (66087025207).

Almost surely, 2132174050413 is an apocalyptic number.

It is an amenable number.

132174050413 is a deficient number, since it is larger than the sum of its proper divisors (1).

132174050413 is an equidigital number, since it uses as much as digits as its factorization.

132174050413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10080, while the sum is 31.

The spelling of 132174050413 in words is "one hundred thirty-two billion, one hundred seventy-four million, fifty thousand, four hundred thirteen".