Base | Representation |
---|---|
bin | 11110000011110001010000… |
… | …111111010100110010110111 |
3 | 122100002020110210221100020121 |
4 | 132003301100333110302313 |
5 | 114311433011222222112 |
6 | 1145100014352112411 |
7 | 36563111305311466 |
oct | 3603612077246267 |
9 | 570066423840217 |
10 | 132200452148407 |
11 | 39139995862a85 |
12 | 129b13bbb35707 |
13 | 589c5aba08256 |
14 | 2490770bca9dd |
15 | 1043c85560407 |
hex | 783c50fd4cb7 |
132200452148407 has 2 divisors, whose sum is σ = 132200452148408. Its totient is φ = 132200452148406.
The previous prime is 132200452148399. The next prime is 132200452148441. The reversal of 132200452148407 is 704841254002231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132200452148407 - 23 = 132200452148399 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132200452148467) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66100226074203 + 66100226074204.
It is an arithmetic number, because the mean of its divisors is an integer number (66100226074204).
Almost surely, 2132200452148407 is an apocalyptic number.
132200452148407 is a deficient number, since it is larger than the sum of its proper divisors (1).
132200452148407 is an equidigital number, since it uses as much as digits as its factorization.
132200452148407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 430080, while the sum is 43.
The spelling of 132200452148407 in words is "one hundred thirty-two trillion, two hundred billion, four hundred fifty-two million, one hundred forty-eight thousand, four hundred seven".
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