Base | Representation |
---|---|
bin | 111101100011111001… |
… | …1010000000100001101 |
3 | 110122020022201201122021 |
4 | 1323013303100010031 |
5 | 4131221441320023 |
6 | 140422104450141 |
7 | 12360031656604 |
oct | 1730763200415 |
9 | 418208651567 |
10 | 132201120013 |
11 | 510800a4186 |
12 | 21755a79951 |
13 | c60ac08c01 |
14 | 6581958a3b |
15 | 368b20235d |
hex | 1ec7cd010d |
132201120013 has 2 divisors, whose sum is σ = 132201120014. Its totient is φ = 132201120012.
The previous prime is 132201119969. The next prime is 132201120049. The reversal of 132201120013 is 310021102231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 129321509769 + 2879610244 = 359613^2 + 53662^2 .
It is an emirp because it is prime and its reverse (310021102231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 132201120013 - 221 = 132199022861 is a prime.
It is a super-2 number, since 2×1322011200132 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132201120113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66100560006 + 66100560007.
It is an arithmetic number, because the mean of its divisors is an integer number (66100560007).
Almost surely, 2132201120013 is an apocalyptic number.
It is an amenable number.
132201120013 is a deficient number, since it is larger than the sum of its proper divisors (1).
132201120013 is an equidigital number, since it uses as much as digits as its factorization.
132201120013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 132201120013 its reverse (310021102231), we get a palindrome (442222222244).
The spelling of 132201120013 in words is "one hundred thirty-two billion, two hundred one million, one hundred twenty thousand, thirteen".
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