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13220241908981 is a prime number
BaseRepresentation
bin1100000001100001001111…
…0100101010010011110101
31201210211202101111201202112
43000120103310222103311
53213100023412041411
644041143441020405
72533062630055322
oct300302364522365
951724671451675
1013220241908981
1142377449a7798
121596208324705
1374b881820c13
14339c1259db49
1517dd4ec0db8b
hexc0613d2a4f5

13220241908981 has 2 divisors, whose sum is σ = 13220241908982. Its totient is φ = 13220241908980.

The previous prime is 13220241908893. The next prime is 13220241908999. The reversal of 13220241908981 is 18980914202231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12810200189956 + 410041719025 = 3579134^2 + 640345^2 .

It is an emirp because it is prime and its reverse (18980914202231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13220241908981 - 230 = 13219168167157 is a prime.

It is a super-2 number, since 2×132202419089812 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13220241958981) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6610120954490 + 6610120954491.

It is an arithmetic number, because the mean of its divisors is an integer number (6610120954491).

Almost surely, 213220241908981 is an apocalyptic number.

It is an amenable number.

13220241908981 is a deficient number, since it is larger than the sum of its proper divisors (1).

13220241908981 is an equidigital number, since it uses as much as digits as its factorization.

13220241908981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 497664, while the sum is 50.

The spelling of 13220241908981 in words is "thirteen trillion, two hundred twenty billion, two hundred forty-one million, nine hundred eight thousand, nine hundred eighty-one".