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132211046094157 is a prime number
BaseRepresentation
bin11110000011111011001000…
…011100000001010101001101
3122100010020211010022112202201
4132003323020130001111031
5114312121210300003112
61145104525513121501
736563634654335632
oct3603731034012515
9570106733275681
10132211046094157
1139143431870248
12129b34779b9291
1358a05a97816c4
142491097b9c189
1510441a5642257
hex783ec870154d

132211046094157 has 2 divisors, whose sum is σ = 132211046094158. Its totient is φ = 132211046094156.

The previous prime is 132211046094031. The next prime is 132211046094173. The reversal of 132211046094157 is 751490640112231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 80648679772521 + 51562366321636 = 8980461^2 + 7180694^2 .

It is an emirp because it is prime and its reverse (751490640112231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 132211046094157 - 235 = 132176686355789 is a prime.

It is a super-2 number, since 2×1322110460941572 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132211046094187) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66105523047078 + 66105523047079.

It is an arithmetic number, because the mean of its divisors is an integer number (66105523047079).

Almost surely, 2132211046094157 is an apocalyptic number.

It is an amenable number.

132211046094157 is a deficient number, since it is larger than the sum of its proper divisors (1).

132211046094157 is an equidigital number, since it uses as much as digits as its factorization.

132211046094157 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 362880, while the sum is 46.

The spelling of 132211046094157 in words is "one hundred thirty-two trillion, two hundred eleven billion, forty-six million, ninety-four thousand, one hundred fifty-seven".