Base | Representation |
---|---|
bin | 111101100100001100… |
… | …1110010101110001101 |
3 | 110122021000202000221011 |
4 | 1323020121302232031 |
5 | 4131232033122222 |
6 | 140423105205221 |
7 | 12360213566626 |
oct | 1731031625615 |
9 | 418230660834 |
10 | 132211223437 |
11 | 51085875017 |
12 | 21759330811 |
13 | c610035877 |
14 | 6583028a4d |
15 | 368c04ac77 |
hex | 1ec8672b8d |
132211223437 has 2 divisors, whose sum is σ = 132211223438. Its totient is φ = 132211223436.
The previous prime is 132211223383. The next prime is 132211223483. The reversal of 132211223437 is 734322112231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 73305021001 + 58906202436 = 270749^2 + 242706^2 .
It is a cyclic number.
It is not a de Polignac number, because 132211223437 - 215 = 132211190669 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 132211223399 and 132211223408.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132211223497) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66105611718 + 66105611719.
It is an arithmetic number, because the mean of its divisors is an integer number (66105611719).
Almost surely, 2132211223437 is an apocalyptic number.
It is an amenable number.
132211223437 is a deficient number, since it is larger than the sum of its proper divisors (1).
132211223437 is an equidigital number, since it uses as much as digits as its factorization.
132211223437 is an evil number, because the sum of its binary digits is even.
The product of its digits is 12096, while the sum is 31.
Adding to 132211223437 its reverse (734322112231), we get a palindrome (866533335668).
The spelling of 132211223437 in words is "one hundred thirty-two billion, two hundred eleven million, two hundred twenty-three thousand, four hundred thirty-seven".
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