Base | Representation |
---|---|
bin | 10011001111010100001… |
… | …010010100010000111111 |
3 | 11200101121102120002210101 |
4 | 103033110022110100333 |
5 | 133130142243342421 |
6 | 2451212044421531 |
7 | 164343141160252 |
oct | 23172412242077 |
9 | 4611542502711 |
10 | 1322114434111 |
11 | 46a784148919 |
12 | 1942995478a7 |
13 | 978a0874b03 |
14 | 47dc25d7099 |
15 | 245d060a191 |
hex | 133d429443f |
1322114434111 has 2 divisors, whose sum is σ = 1322114434112. Its totient is φ = 1322114434110.
The previous prime is 1322114434093. The next prime is 1322114434181. The reversal of 1322114434111 is 1114344112231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1322114434111 - 221 = 1322112336959 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1322114434111.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1322114434181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661057217055 + 661057217056.
It is an arithmetic number, because the mean of its divisors is an integer number (661057217056).
Almost surely, 21322114434111 is an apocalyptic number.
1322114434111 is a deficient number, since it is larger than the sum of its proper divisors (1).
1322114434111 is an equidigital number, since it uses as much as digits as its factorization.
1322114434111 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2304, while the sum is 28.
Adding to 1322114434111 its reverse (1114344112231), we get a palindrome (2436458546342).
The spelling of 1322114434111 in words is "one trillion, three hundred twenty-two billion, one hundred fourteen million, four hundred thirty-four thousand, one hundred eleven".
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