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132212112301117 is a prime number
BaseRepresentation
bin11110000011111100000111…
…111111010001110000111101
3122100010100120102120110202101
4132003330013333101300331
5114312130401222113432
61145105223401425101
736564003252055012
oct3603740777216075
9570110512513671
10132212112301117
11391439296a4322
12129b3714a9b191
1358a071962cab4
142491159621709
1510442190504e7
hex783f07fd1c3d

132212112301117 has 2 divisors, whose sum is σ = 132212112301118. Its totient is φ = 132212112301116.

The previous prime is 132212112301081. The next prime is 132212112301187. The reversal of 132212112301117 is 711103211212231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 124791821892676 + 7420290408441 = 11171026^2 + 2724021^2 .

It is a cyclic number.

It is not a de Polignac number, because 132212112301117 - 235 = 132177752562749 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132212112301187) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66106056150558 + 66106056150559.

It is an arithmetic number, because the mean of its divisors is an integer number (66106056150559).

Almost surely, 2132212112301117 is an apocalyptic number.

It is an amenable number.

132212112301117 is a deficient number, since it is larger than the sum of its proper divisors (1).

132212112301117 is an equidigital number, since it uses as much as digits as its factorization.

132212112301117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1008, while the sum is 28.

Adding to 132212112301117 its reverse (711103211212231), we get a palindrome (843315323513348).

The spelling of 132212112301117 in words is "one hundred thirty-two trillion, two hundred twelve billion, one hundred twelve million, three hundred one thousand, one hundred seventeen".