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132212168455781 is a prime number
BaseRepresentation
bin11110000011111100001011…
…010101011111011001100101
3122100010100201100020102110202
4132003330023111133121211
5114312131010111041111
61145105233125200245
736564004533265151
oct3603741325373145
9570110640212422
10132212168455781
1139143958369137
12129b372b860085
1358a07281616cb
142491162c7c061
15104421de43b3b
hex783f0b55f665

132212168455781 has 2 divisors, whose sum is σ = 132212168455782. Its totient is φ = 132212168455780.

The previous prime is 132212168455723. The next prime is 132212168455811. The reversal of 132212168455781 is 187554861212231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 108062158137025 + 24150010318756 = 10395295^2 + 4914266^2 .

It is a cyclic number.

It is not a de Polignac number, because 132212168455781 - 210 = 132212168454757 is a prime.

It is a super-2 number, since 2×1322121684557812 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132212168455181) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66106084227890 + 66106084227891.

It is an arithmetic number, because the mean of its divisors is an integer number (66106084227891).

Almost surely, 2132212168455781 is an apocalyptic number.

It is an amenable number.

132212168455781 is a deficient number, since it is larger than the sum of its proper divisors (1).

132212168455781 is an equidigital number, since it uses as much as digits as its factorization.

132212168455781 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6451200, while the sum is 56.

The spelling of 132212168455781 in words is "one hundred thirty-two trillion, two hundred twelve billion, one hundred sixty-eight million, four hundred fifty-five thousand, seven hundred eighty-one".