Base | Representation |
---|---|
bin | 11110000011111100010100… |
… | …011111010000111110010001 |
3 | 122100010101010001011221110212 |
4 | 132003330110133100332101 |
5 | 114312131313413404243 |
6 | 1145105300252333505 |
7 | 36564011406432101 |
oct | 3603742437207621 |
9 | 570111101157425 |
10 | 132212322013073 |
11 | 39143a2700aa95 |
12 | 129b3773174295 |
13 | 58a0750c07803 |
14 | 2491179411201 |
15 | 104422c677318 |
hex | 783f147d0f91 |
132212322013073 has 2 divisors, whose sum is σ = 132212322013074. Its totient is φ = 132212322013072.
The previous prime is 132212322013063. The next prime is 132212322013127. The reversal of 132212322013073 is 370310223212231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 130710013391104 + 1502308621969 = 11432848^2 + 1225687^2 .
It is a cyclic number.
It is not a de Polignac number, because 132212322013073 - 210 = 132212322012049 is a prime.
It is not a weakly prime, because it can be changed into another prime (132212322013033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66106161006536 + 66106161006537.
It is an arithmetic number, because the mean of its divisors is an integer number (66106161006537).
Almost surely, 2132212322013073 is an apocalyptic number.
It is an amenable number.
132212322013073 is a deficient number, since it is larger than the sum of its proper divisors (1).
132212322013073 is an equidigital number, since it uses as much as digits as its factorization.
132212322013073 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18144, while the sum is 32.
The spelling of 132212322013073 in words is "one hundred thirty-two trillion, two hundred twelve billion, three hundred twenty-two million, thirteen thousand, seventy-three".
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