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132213010100987 is a prime number
BaseRepresentation
bin11110000011111100111101…
…100000000111001011111011
3122100010102212222221102122102
4132003330331200013023323
5114312134221041212422
61145105452432414015
736564034433201234
oct3603747540071373
9570112788842572
10132213010100987
113914424a463692
12129b39256a730b
1358a0830635c1a
14249120296808b
15104426cc95192
hex783f3d8072fb

132213010100987 has 2 divisors, whose sum is σ = 132213010100988. Its totient is φ = 132213010100986.

The previous prime is 132213010100929. The next prime is 132213010101013. The reversal of 132213010100987 is 789001010312231.

It is a strong prime.

It is an emirp because it is prime and its reverse (789001010312231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 132213010100987 - 216 = 132213010035451 is a prime.

It is a super-3 number, since 3×1322130101009873 (a number of 43 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 132213010100987.

It is not a weakly prime, because it can be changed into another prime (132213010100887) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66106505050493 + 66106505050494.

It is an arithmetic number, because the mean of its divisors is an integer number (66106505050494).

Almost surely, 2132213010100987 is an apocalyptic number.

132213010100987 is a deficient number, since it is larger than the sum of its proper divisors (1).

132213010100987 is an equidigital number, since it uses as much as digits as its factorization.

132213010100987 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18144, while the sum is 38.

The spelling of 132213010100987 in words is "one hundred thirty-two trillion, two hundred thirteen billion, ten million, one hundred thousand, nine hundred eighty-seven".