Base | Representation |
---|---|
bin | 1100000001100101001110… |
… | …0100001001011111010011 |
3 | 1201210221111220210112201121 |
4 | 3000121103210021133103 |
5 | 3213104221144301232 |
6 | 44041441522143111 |
7 | 2533131263656612 |
oct | 300312344113723 |
9 | 51727456715647 |
10 | 13221311322067 |
11 | 4238143620662 |
12 | 15964664b1a97 |
13 | 74b9c2252724 |
14 | 339cb4619879 |
15 | 17ddb3a51d97 |
hex | c06539097d3 |
13221311322067 has 2 divisors, whose sum is σ = 13221311322068. Its totient is φ = 13221311322066.
The previous prime is 13221311322007. The next prime is 13221311322113. The reversal of 13221311322067 is 76022311312231.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13221311322067 is a prime.
It is a super-3 number, since 3×132213113220673 (a number of 40 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (13221311322007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6610655661033 + 6610655661034.
It is an arithmetic number, because the mean of its divisors is an integer number (6610655661034).
Almost surely, 213221311322067 is an apocalyptic number.
13221311322067 is a deficient number, since it is larger than the sum of its proper divisors (1).
13221311322067 is an equidigital number, since it uses as much as digits as its factorization.
13221311322067 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18144, while the sum is 34.
Adding to 13221311322067 its reverse (76022311312231), we get a palindrome (89243622634298).
The spelling of 13221311322067 in words is "thirteen trillion, two hundred twenty-one billion, three hundred eleven million, three hundred twenty-two thousand, sixty-seven".
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