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132214143310397 is a prime number
BaseRepresentation
bin11110000011111110000001…
…000010111101101000111101
3122100010112210222021102201022
4132003332001002331220331
5114312144031141413042
61145110201113153525
736564104503260611
oct3603760102755075
9570115728242638
10132214143310397
11391447810a0695
12129b3ba10bb8a5
1358a0981343635
1424912ad26d341
1510442d74dacd2
hex783f810bda3d

132214143310397 has 2 divisors, whose sum is σ = 132214143310398. Its totient is φ = 132214143310396.

The previous prime is 132214143310391. The next prime is 132214143310463. The reversal of 132214143310397 is 793013341412231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 131340630635236 + 873512675161 = 11460394^2 + 934619^2 .

It is a cyclic number.

It is not a de Polignac number, because 132214143310397 - 28 = 132214143310141 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132214143310391) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66107071655198 + 66107071655199.

It is an arithmetic number, because the mean of its divisors is an integer number (66107071655199).

Almost surely, 2132214143310397 is an apocalyptic number.

It is an amenable number.

132214143310397 is a deficient number, since it is larger than the sum of its proper divisors (1).

132214143310397 is an equidigital number, since it uses as much as digits as its factorization.

132214143310397 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 326592, while the sum is 44.

The spelling of 132214143310397 in words is "one hundred thirty-two trillion, two hundred fourteen billion, one hundred forty-three million, three hundred ten thousand, three hundred ninety-seven".