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13221433412207 is a prime number
BaseRepresentation
bin1100000001100101101011…
…0101111000101001101111
31201210221211102112100220122
43000121122311320221233
53213104443423142312
644041502003035155
72533134305504546
oct300313265705157
951727742470818
1013221433412207
1142381a652a7a9
12159649b36babb
1374ba1162bb07
14339cc691b15d
1517ddbe61bb72
hexc065ad78a6f

13221433412207 has 2 divisors, whose sum is σ = 13221433412208. Its totient is φ = 13221433412206.

The previous prime is 13221433412191. The next prime is 13221433412251. The reversal of 13221433412207 is 70221433412231.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13221433412207 - 24 = 13221433412191 is a prime.

It is a super-2 number, since 2×132214334122072 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13221433415207) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6610716706103 + 6610716706104.

It is an arithmetic number, because the mean of its divisors is an integer number (6610716706104).

Almost surely, 213221433412207 is an apocalyptic number.

13221433412207 is a deficient number, since it is larger than the sum of its proper divisors (1).

13221433412207 is an equidigital number, since it uses as much as digits as its factorization.

13221433412207 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48384, while the sum is 35.

Adding to 13221433412207 its reverse (70221433412231), we get a palindrome (83442866824438).

The spelling of 13221433412207 in words is "thirteen trillion, two hundred twenty-one billion, four hundred thirty-three million, four hundred twelve thousand, two hundred seven".