Base | Representation |
---|---|
bin | 1100000001100111110010… |
… | …1011001100101111101011 |
3 | 1201211000021222121122201222 |
4 | 3000121330223030233223 |
5 | 3213112124231130032 |
6 | 44042034201132255 |
7 | 2533154340311312 |
oct | 300317453145753 |
9 | 51730258548658 |
10 | 13222001036267 |
11 | 42384679850a1 |
12 | 159661948a08b |
13 | 74baa210013a |
14 | 339d3c077279 |
15 | 17de04391a12 |
hex | c067caccbeb |
13222001036267 has 2 divisors, whose sum is σ = 13222001036268. Its totient is φ = 13222001036266.
The previous prime is 13222001036227. The next prime is 13222001036269. The reversal of 13222001036267 is 76263010022231.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13222001036267 is a prime.
It is a super-2 number, since 2×132220010362672 (a number of 27 digits) contains 22 as substring.
Together with 13222001036269, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (13222001036269) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6611000518133 + 6611000518134.
It is an arithmetic number, because the mean of its divisors is an integer number (6611000518134).
Almost surely, 213222001036267 is an apocalyptic number.
13222001036267 is a deficient number, since it is larger than the sum of its proper divisors (1).
13222001036267 is an equidigital number, since it uses as much as digits as its factorization.
13222001036267 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36288, while the sum is 35.
Adding to 13222001036267 its reverse (76263010022231), we get a palindrome (89485011058498).
The spelling of 13222001036267 in words is "thirteen trillion, two hundred twenty-two billion, one million, thirty-six thousand, two hundred sixty-seven".
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