Base | Representation |
---|---|
bin | 10011001111011001010… |
… | …010010101001111000101 |
3 | 11200101211102100201001201 |
4 | 103033121102111033011 |
5 | 133130331301440232 |
6 | 2451224355422501 |
7 | 164345234100646 |
oct | 23173122251705 |
9 | 4611742321051 |
10 | 1322200421317 |
11 | 46a818739326 |
12 | 1943022b4a31 |
13 | 978b5620409 |
14 | 47dcdbbb6cd |
15 | 245d7e42be7 |
hex | 133d94953c5 |
1322200421317 has 2 divisors, whose sum is σ = 1322200421318. Its totient is φ = 1322200421316.
The previous prime is 1322200421309. The next prime is 1322200421393. The reversal of 1322200421317 is 7131240022231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1132161968961 + 190038452356 = 1064031^2 + 435934^2 .
It is a cyclic number.
It is not a de Polignac number, because 1322200421317 - 23 = 1322200421309 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1322200421117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661100210658 + 661100210659.
It is an arithmetic number, because the mean of its divisors is an integer number (661100210659).
Almost surely, 21322200421317 is an apocalyptic number.
It is an amenable number.
1322200421317 is a deficient number, since it is larger than the sum of its proper divisors (1).
1322200421317 is an equidigital number, since it uses as much as digits as its factorization.
1322200421317 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4032, while the sum is 28.
Adding to 1322200421317 its reverse (7131240022231), we get a palindrome (8453440443548).
The spelling of 1322200421317 in words is "one trillion, three hundred twenty-two billion, two hundred million, four hundred twenty-one thousand, three hundred seventeen".
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