Base | Representation |
---|---|
bin | 11110000100000011110000… |
… | …111100100011011011000101 |
3 | 122100011010202010121112220012 |
4 | 132010003300330203123011 |
5 | 114312244201301130022 |
6 | 1145113101403520005 |
7 | 36564413452252232 |
oct | 3604036074433305 |
9 | 570133663545805 |
10 | 132220315645637 |
11 | 3914735922949a |
12 | 129b5224229005 |
13 | 58a142602b5cb |
14 | 24916d6cdc789 |
15 | 1044549315de2 |
hex | 7840f0f236c5 |
132220315645637 has 2 divisors, whose sum is σ = 132220315645638. Its totient is φ = 132220315645636.
The previous prime is 132220315645619. The next prime is 132220315645777. The reversal of 132220315645637 is 736546513022231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 92789564314756 + 39430751330881 = 9632734^2 + 6279391^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132220315645637 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132220315645037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66110157822818 + 66110157822819.
It is an arithmetic number, because the mean of its divisors is an integer number (66110157822819).
Almost surely, 2132220315645637 is an apocalyptic number.
It is an amenable number.
132220315645637 is a deficient number, since it is larger than the sum of its proper divisors (1).
132220315645637 is an equidigital number, since it uses as much as digits as its factorization.
132220315645637 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5443200, while the sum is 50.
Adding to 132220315645637 its reverse (736546513022231), we get a palindrome (868766828667868).
The spelling of 132220315645637 in words is "one hundred thirty-two trillion, two hundred twenty billion, three hundred fifteen million, six hundred forty-five thousand, six hundred thirty-seven".
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