Base | Representation |
---|---|
bin | 111101100100100000… |
… | …0010001010010110011 |
3 | 110122021201201111021102 |
4 | 1323021000101102303 |
5 | 4131242123411011 |
6 | 140424105315015 |
7 | 12360365410121 |
oct | 1731100212263 |
9 | 418251644242 |
10 | 132221310131 |
11 | 51090534329 |
12 | 21760795a6b |
13 | c612157a21 |
14 | 65844d2911 |
15 | 368cd8e73b |
hex | 1ec90114b3 |
132221310131 has 2 divisors, whose sum is σ = 132221310132. Its totient is φ = 132221310130.
The previous prime is 132221310119. The next prime is 132221310241. The reversal of 132221310131 is 131013122231.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (131013122231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 132221310131 - 214 = 132221293747 is a prime.
It is a super-3 number, since 3×1322213101313 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (132221310101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66110655065 + 66110655066.
It is an arithmetic number, because the mean of its divisors is an integer number (66110655066).
Almost surely, 2132221310131 is an apocalyptic number.
132221310131 is a deficient number, since it is larger than the sum of its proper divisors (1).
132221310131 is an equidigital number, since it uses as much as digits as its factorization.
132221310131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 132221310131 its reverse (131013122231), we get a palindrome (263234432362).
The spelling of 132221310131 in words is "one hundred thirty-two billion, two hundred twenty-one million, three hundred ten thousand, one hundred thirty-one".
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