Base | Representation |
---|---|
bin | 111101100100100001… |
… | …0111001101101111001 |
3 | 110122021210000112120212 |
4 | 1323021002321231321 |
5 | 4131242312444433 |
6 | 140424132200505 |
7 | 12360404312306 |
oct | 1731102715571 |
9 | 418253015525 |
10 | 132221999993 |
11 | 51090965666 |
12 | 21760a69135 |
13 | c612339a25 |
14 | 65846320ad |
15 | 368ce78d48 |
hex | 1ec90b9b79 |
132221999993 has 2 divisors, whose sum is σ = 132221999994. Its totient is φ = 132221999992.
The previous prime is 132221999971. The next prime is 132222000047. The reversal of 132221999993 is 399999122231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 75519436864 + 56702563129 = 274808^2 + 238123^2 .
It is an emirp because it is prime and its reverse (399999122231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 132221999993 - 212 = 132221995897 is a prime.
It is not a weakly prime, because it can be changed into another prime (132221999963) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66110999996 + 66110999997.
It is an arithmetic number, because the mean of its divisors is an integer number (66110999997).
Almost surely, 2132221999993 is an apocalyptic number.
It is an amenable number.
132221999993 is a deficient number, since it is larger than the sum of its proper divisors (1).
132221999993 is an equidigital number, since it uses as much as digits as its factorization.
132221999993 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 4251528, while the sum is 59.
The spelling of 132221999993 in words is "one hundred thirty-two billion, two hundred twenty-one million, nine hundred ninety-nine thousand, nine hundred ninety-three".
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