Base | Representation |
---|---|
bin | 111101100100100001… |
… | …0111001101110101111 |
3 | 110122021210000112122212 |
4 | 1323021002321232233 |
5 | 4131242313000142 |
6 | 140424132201035 |
7 | 12360404312414 |
oct | 1731102715657 |
9 | 418253015585 |
10 | 132222000047 |
11 | 51090965705 |
12 | 21760a6917b |
13 | c612339a67 |
14 | 658463210b |
15 | 368ce78d82 |
hex | 1ec90b9baf |
132222000047 has 2 divisors, whose sum is σ = 132222000048. Its totient is φ = 132222000046.
The previous prime is 132221999993. The next prime is 132222000049. The reversal of 132222000047 is 740000222231.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132222000047 - 210 = 132221999023 is a prime.
Together with 132222000049, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 132221999986 and 132222000031.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132222000049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66111000023 + 66111000024.
It is an arithmetic number, because the mean of its divisors is an integer number (66111000024).
Almost surely, 2132222000047 is an apocalyptic number.
132222000047 is a deficient number, since it is larger than the sum of its proper divisors (1).
132222000047 is an equidigital number, since it uses as much as digits as its factorization.
132222000047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1344, while the sum is 23.
Adding to 132222000047 its reverse (740000222231), we get a palindrome (872222222278).
The spelling of 132222000047 in words is "one hundred thirty-two billion, two hundred twenty-two million, forty-seven", and thus it is an aban number.
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