Base | Representation |
---|---|
bin | 10011001111011011101… |
… | …110011011010000000111 |
3 | 11200101221021100121112011 |
4 | 103033123232123100013 |
5 | 133130422240343143 |
6 | 2451232420435051 |
7 | 164346241644433 |
oct | 23173356332007 |
9 | 4611837317464 |
10 | 1322241340423 |
11 | 46a839847473 |
12 | 194313b48a87 |
13 | 978c0c493c3 |
14 | 47dd53cd9c3 |
15 | 245db826e9d |
hex | 133dbb9b407 |
1322241340423 has 2 divisors, whose sum is σ = 1322241340424. Its totient is φ = 1322241340422.
The previous prime is 1322241340411. The next prime is 1322241340429. The reversal of 1322241340423 is 3240431422231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1322241340423 - 229 = 1321704469511 is a prime.
It is a super-2 number, since 2×13222413404232 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1322241340429) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661120670211 + 661120670212.
It is an arithmetic number, because the mean of its divisors is an integer number (661120670212).
Almost surely, 21322241340423 is an apocalyptic number.
1322241340423 is a deficient number, since it is larger than the sum of its proper divisors (1).
1322241340423 is an equidigital number, since it uses as much as digits as its factorization.
1322241340423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 27648, while the sum is 31.
Adding to 1322241340423 its reverse (3240431422231), we get a palindrome (4562672762654).
The spelling of 1322241340423 in words is "one trillion, three hundred twenty-two billion, two hundred forty-one million, three hundred forty thousand, four hundred twenty-three".
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