Base | Representation |
---|---|
bin | 11110000100001001010101… |
… | …111101010100001110100010 |
3 | 122100011201012120020010000011 |
4 | 132010021111331110032202 |
5 | 114312343433124433100 |
6 | 1145115532011115134 |
7 | 36565015052500324 |
oct | 3604112575241642 |
9 | 570151176203004 |
10 | 132226305311650 |
11 | 391499522411a0 |
12 | 129b6416142aaa |
13 | 58a1b6bc19794 |
14 | 2491b045bb614 |
15 | 104479a0abbba |
hex | 784255f543a2 |
132226305311650 has 48 divisors (see below), whose sum is σ = 272303659709280. Its totient is φ = 47364646665600.
The previous prime is 132226305311561. The next prime is 132226305311671. The reversal of 132226305311650 is 56113503622231.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1794078555 + ... + 1794152254.
It is an arithmetic number, because the mean of its divisors is an integer number (5672992910610).
Almost surely, 2132226305311650 is an apocalyptic number.
132226305311650 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
132226305311650 is an abundant number, since it is smaller than the sum of its proper divisors (140077354397630).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132226305311650 is a wasteful number, since it uses less digits than its factorization.
132226305311650 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3588230899 (or 3588230894 counting only the distinct ones).
The product of its (nonzero) digits is 194400, while the sum is 40.
Adding to 132226305311650 its reverse (56113503622231), we get a palindrome (188339808933881).
The spelling of 132226305311650 in words is "one hundred thirty-two trillion, two hundred twenty-six billion, three hundred five million, three hundred eleven thousand, six hundred fifty".
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