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13222999981 is a prime number
BaseRepresentation
bin11000101000010011…
…01111011110101101
31021010112101222221001
430110021233132231
5204040041444411
610024034440301
7645451434232
oct142411573655
937115358831
1013222999981
115676047664
122690433091
13132964ca59
148d6217789
15525d00dc1
hex31426f7ad

13222999981 has 2 divisors, whose sum is σ = 13222999982. Its totient is φ = 13222999980.

The previous prime is 13222999903. The next prime is 13223000029. The reversal of 13222999981 is 18999922231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9842624100 + 3380375881 = 99210^2 + 58141^2 .

It is a cyclic number.

It is not a de Polignac number, because 13222999981 - 29 = 13222999469 is a prime.

It is a super-2 number, since 2×132229999812 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13222999481) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6611499990 + 6611499991.

It is an arithmetic number, because the mean of its divisors is an integer number (6611499991).

Almost surely, 213222999981 is an apocalyptic number.

It is an amenable number.

13222999981 is a deficient number, since it is larger than the sum of its proper divisors (1).

13222999981 is an equidigital number, since it uses as much as digits as its factorization.

13222999981 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1259712, while the sum is 55.

The spelling of 13222999981 in words is "thirteen billion, two hundred twenty-two million, nine hundred ninety-nine thousand, nine hundred eighty-one".