Base | Representation |
---|---|
bin | 11000101000010011… |
… | …10100101100001001 |
3 | 1021010112110002012102 |
4 | 30110021310230021 |
5 | 204040043140241 |
6 | 10024035123145 |
7 | 645451553366 |
oct | 142411645411 |
9 | 37115402172 |
10 | 13223021321 |
11 | 56760616a4 |
12 | 26904434b5 |
13 | 1329659693 |
14 | 8d622146d |
15 | 525d0739b |
hex | 314274b09 |
13223021321 has 2 divisors, whose sum is σ = 13223021322. Its totient is φ = 13223021320.
The previous prime is 13223021299. The next prime is 13223021323. The reversal of 13223021321 is 12312032231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7303411600 + 5919609721 = 85460^2 + 76939^2 .
It is a cyclic number.
It is not a de Polignac number, because 13223021321 - 214 = 13223004937 is a prime.
Together with 13223021323, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 13223021293 and 13223021302.
It is not a weakly prime, because it can be changed into another prime (13223021323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6611510660 + 6611510661.
It is an arithmetic number, because the mean of its divisors is an integer number (6611510661).
Almost surely, 213223021321 is an apocalyptic number.
It is an amenable number.
13223021321 is a deficient number, since it is larger than the sum of its proper divisors (1).
13223021321 is an equidigital number, since it uses as much as digits as its factorization.
13223021321 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 13223021321 its reverse (12312032231), we get a palindrome (25535053552).
The spelling of 13223021321 in words is "thirteen billion, two hundred twenty-three million, twenty-one thousand, three hundred twenty-one".
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