Base | Representation |
---|---|
bin | 11000101000010100… |
… | …01101010001001101 |
3 | 1021010112122012022011 |
4 | 30110022031101031 |
5 | 204040104400442 |
6 | 10024041221221 |
7 | 645452453041 |
oct | 142412152115 |
9 | 37115565264 |
10 | 13223121997 |
11 | 56761202a8 |
12 | 2690491811 |
13 | 1329693457 |
14 | 8d624a021 |
15 | 525d27117 |
hex | 31428d44d |
13223121997 has 2 divisors, whose sum is σ = 13223121998. Its totient is φ = 13223121996.
The previous prime is 13223121913. The next prime is 13223122021. The reversal of 13223121997 is 79912132231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9996200361 + 3226921636 = 99981^2 + 56806^2 .
It is an emirp because it is prime and its reverse (79912132231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13223121997 - 27 = 13223121869 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13223121907) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6611560998 + 6611560999.
It is an arithmetic number, because the mean of its divisors is an integer number (6611560999).
Almost surely, 213223121997 is an apocalyptic number.
It is an amenable number.
13223121997 is a deficient number, since it is larger than the sum of its proper divisors (1).
13223121997 is an equidigital number, since it uses as much as digits as its factorization.
13223121997 is an evil number, because the sum of its binary digits is even.
The product of its digits is 40824, while the sum is 40.
The spelling of 13223121997 in words is "thirteen billion, two hundred twenty-three million, one hundred twenty-one thousand, nine hundred ninety-seven".
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