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1322320101497 is a prime number
BaseRepresentation
bin10011001111100000011…
…010111000000001111001
311200102010202120002101222
4103033200122320001321
5133131102421221442
62451244312521425
7164351216260523
oct23174032700171
94612122502358
101322320101497
1146a87a25186a
121943363b0275
13979043648a5
1448001a52a13
15245e36d38d2
hex133e06b8079

1322320101497 has 2 divisors, whose sum is σ = 1322320101498. Its totient is φ = 1322320101496.

The previous prime is 1322320101469. The next prime is 1322320101499. The reversal of 1322320101497 is 7941010232231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 767383008016 + 554937093481 = 876004^2 + 744941^2 .

It is a cyclic number.

It is not a de Polignac number, because 1322320101497 - 28 = 1322320101241 is a prime.

Together with 1322320101499, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1322320101499) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661160050748 + 661160050749.

It is an arithmetic number, because the mean of its divisors is an integer number (661160050749).

Almost surely, 21322320101497 is an apocalyptic number.

It is an amenable number.

1322320101497 is a deficient number, since it is larger than the sum of its proper divisors (1).

1322320101497 is an equidigital number, since it uses as much as digits as its factorization.

1322320101497 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18144, while the sum is 35.

The spelling of 1322320101497 in words is "one trillion, three hundred twenty-two billion, three hundred twenty million, one hundred one thousand, four hundred ninety-seven".