Base | Representation |
---|---|
bin | 11110000100010000101001… |
… | …000101000110011111111010 |
3 | 122100012110102201221000000202 |
4 | 132010100221011012133322 |
5 | 114313011010412444232 |
6 | 1145123305405202202 |
7 | 36565413214060202 |
oct | 3604205105063772 |
9 | 570173381830022 |
10 | 132234142312442 |
11 | 39152203aa8955 |
12 | 129b7a42860362 |
13 | 58a281a75bc61 |
14 | 2492249375402 |
15 | 1044aa810b162 |
hex | 7844291467fa |
132234142312442 has 4 divisors (see below), whose sum is σ = 198351213468666. Its totient is φ = 66117071156220.
The previous prime is 132234142312399. The next prime is 132234142312511. The reversal of 132234142312442 is 244213241432231.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 110792065659961 + 21442076652481 = 10525781^2 + 4630559^2 .
It is a junction number, because it is equal to n+sod(n) for n = 132234142312396 and 132234142312405.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33058535578109 + ... + 33058535578112.
Almost surely, 2132234142312442 is an apocalyptic number.
132234142312442 is a deficient number, since it is larger than the sum of its proper divisors (66117071156224).
132234142312442 is an equidigital number, since it uses as much as digits as its factorization.
132234142312442 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 66117071156223.
The product of its digits is 221184, while the sum is 38.
Adding to 132234142312442 its reverse (244213241432231), we get a palindrome (376447383744673).
The spelling of 132234142312442 in words is "one hundred thirty-two trillion, two hundred thirty-four billion, one hundred forty-two million, three hundred twelve thousand, four hundred forty-two".
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