Base | Representation |
---|---|
bin | 11110000100010000101001… |
… | …000101000110100000111111 |
3 | 122100012110102201221000010022 |
4 | 132010100221011012200333 |
5 | 114313011010413000021 |
6 | 1145123305405202355 |
7 | 36565413214060331 |
oct | 3604205105064077 |
9 | 570173381830108 |
10 | 132234142312511 |
11 | 39152203aa8a08 |
12 | 129b7a428603bb |
13 | 58a281a75bcb5 |
14 | 2492249375451 |
15 | 1044aa810b1ab |
hex | 78442914683f |
132234142312511 has 2 divisors, whose sum is σ = 132234142312512. Its totient is φ = 132234142312510.
The previous prime is 132234142312399. The next prime is 132234142312541. The reversal of 132234142312511 is 115213241432231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132234142312511 - 238 = 131959264405567 is a prime.
It is a super-3 number, since 3×1322341423125113 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132234142312541) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66117071156255 + 66117071156256.
It is an arithmetic number, because the mean of its divisors is an integer number (66117071156256).
Almost surely, 2132234142312511 is an apocalyptic number.
132234142312511 is a deficient number, since it is larger than the sum of its proper divisors (1).
132234142312511 is an equidigital number, since it uses as much as digits as its factorization.
132234142312511 is an evil number, because the sum of its binary digits is even.
The product of its digits is 34560, while the sum is 35.
Adding to 132234142312511 its reverse (115213241432231), we get a palindrome (247447383744742).
The spelling of 132234142312511 in words is "one hundred thirty-two trillion, two hundred thirty-four billion, one hundred forty-two million, three hundred twelve thousand, five hundred eleven".
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