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13224119 is a prime number
BaseRepresentation
bin110010011100…
…100010110111
3220212212002012
4302130202313
511341132434
61151234435
7220255166
oct62344267
926785065
1013224119
117512527
124518a1b
13298022c
141a833dd
1512633ce
hexc9c8b7

13224119 has 2 divisors, whose sum is σ = 13224120. Its totient is φ = 13224118.

The previous prime is 13224097. The next prime is 13224131. The reversal of 13224119 is 91142231.

It is a strong prime.

It is an emirp because it is prime and its reverse (91142231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13224119 - 28 = 13223863 is a prime.

It is a super-2 number, since 2×132241192 = 349754646652322, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 13224094 and 13224103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13224139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6612059 + 6612060.

It is an arithmetic number, because the mean of its divisors is an integer number (6612060).

Almost surely, 213224119 is an apocalyptic number.

13224119 is a deficient number, since it is larger than the sum of its proper divisors (1).

13224119 is an equidigital number, since it uses as much as digits as its factorization.

13224119 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 432, while the sum is 23.

The square root of 13224119 is about 3636.4981781929. The cubic root of 13224119 is about 236.4770049172.

The spelling of 13224119 in words is "thirteen million, two hundred twenty-four thousand, one hundred nineteen".