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132242055331 is a prime number
BaseRepresentation
bin111101100101000111…
…1011010000010100011
3110122100011202110100011
41323022033122002203
54131312431232311
6140430130105351
712361036631551
oct1731217320243
9418304673304
10132242055331
11510a1213521
122176771b257
13c61653c3a9
146587172bd1
15368eadb321
hex1eca3da0a3

132242055331 has 2 divisors, whose sum is σ = 132242055332. Its totient is φ = 132242055330.

The previous prime is 132242055329. The next prime is 132242055397. The reversal of 132242055331 is 133550242231.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 132242055331 - 21 = 132242055329 is a prime.

It is a super-2 number, since 2×1322420553312 (a number of 23 digits) contains 22 as substring.

Together with 132242055329, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 132242055293 and 132242055302.

It is not a weakly prime, because it can be changed into another prime (132242055301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66121027665 + 66121027666.

It is an arithmetic number, because the mean of its divisors is an integer number (66121027666).

Almost surely, 2132242055331 is an apocalyptic number.

132242055331 is a deficient number, since it is larger than the sum of its proper divisors (1).

132242055331 is an equidigital number, since it uses as much as digits as its factorization.

132242055331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 132242055331 its reverse (133550242231), we get a palindrome (265792297562).

The spelling of 132242055331 in words is "one hundred thirty-two billion, two hundred forty-two million, fifty-five thousand, three hundred thirty-one".