Base | Representation |
---|---|
bin | 1111110000111… |
… | …10001001110001 |
3 | 100012211200202221 |
4 | 13320132021301 |
5 | 232323302311 |
6 | 21042241041 |
7 | 3164025154 |
oct | 770361161 |
9 | 305750687 |
10 | 132244081 |
11 | 68714a32 |
12 | 38356181 |
13 | 21523048 |
14 | 137c5c9b |
15 | b923671 |
hex | 7e1e271 |
132244081 has 2 divisors, whose sum is σ = 132244082. Its totient is φ = 132244080.
The previous prime is 132244033. The next prime is 132244117. The reversal of 132244081 is 180442231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 105370225 + 26873856 = 10265^2 + 5184^2 .
It is an emirp because it is prime and its reverse (180442231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 132244081 - 29 = 132243569 is a prime.
It is a super-2 number, since 2×1322440812 = 34976993919069122, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (132244001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66122040 + 66122041.
It is an arithmetic number, because the mean of its divisors is an integer number (66122041).
Almost surely, 2132244081 is an apocalyptic number.
It is an amenable number.
132244081 is a deficient number, since it is larger than the sum of its proper divisors (1).
132244081 is an equidigital number, since it uses as much as digits as its factorization.
132244081 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1536, while the sum is 25.
The square root of 132244081 is about 11499.7426492944. The cubic root of 132244081 is about 509.4779753972.
The spelling of 132244081 in words is "one hundred thirty-two million, two hundred forty-four thousand, eighty-one".
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