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132251202152207 is a prime number
BaseRepresentation
bin11110000100100000100001…
…111011001110011100001111
3122100021002110200000122122222
4132010200201323032130033
5114313300430222332312
61145135210304525555
736566556035240315
oct3604404173163417
9570232420018588
10132251202152207
1139159468918a86
12129bb2040208bb
1358a4308c743b8
142492dc6d900b5
151045255ba3672
hex784821ece70f

132251202152207 has 2 divisors, whose sum is σ = 132251202152208. Its totient is φ = 132251202152206.

The previous prime is 132251202152143. The next prime is 132251202152233. The reversal of 132251202152207 is 702251202152231.

It is a strong prime.

It is an emirp because it is prime and its reverse (702251202152231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 132251202152207 - 26 = 132251202152143 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132251202154207) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66125601076103 + 66125601076104.

It is an arithmetic number, because the mean of its divisors is an integer number (66125601076104).

Almost surely, 2132251202152207 is an apocalyptic number.

132251202152207 is a deficient number, since it is larger than the sum of its proper divisors (1).

132251202152207 is an equidigital number, since it uses as much as digits as its factorization.

132251202152207 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 33600, while the sum is 35.

The spelling of 132251202152207 in words is "one hundred thirty-two trillion, two hundred fifty-one billion, two hundred two million, one hundred fifty-two thousand, two hundred seven".