Base | Representation |
---|---|
bin | 11110000100100000101001… |
… | …101111010000001110111111 |
3 | 122100021002210210200011201111 |
4 | 132010200221233100032333 |
5 | 114313301212301402201 |
6 | 1145135231310222451 |
7 | 36566562216344662 |
oct | 3604405157201677 |
9 | 570232723604644 |
10 | 132251333231551 |
11 | 39159525907916 |
12 | 129bb23bab4a27 |
13 | 58a432a17a241 |
14 | 2492dda5516d9 |
15 | 1045262446b51 |
hex | 784829bd03bf |
132251333231551 has 2 divisors, whose sum is σ = 132251333231552. Its totient is φ = 132251333231550.
The previous prime is 132251333231449. The next prime is 132251333231603. The reversal of 132251333231551 is 155132333152231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132251333231551 - 223 = 132251324842943 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132251333231951) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66125666615775 + 66125666615776.
It is an arithmetic number, because the mean of its divisors is an integer number (66125666615776).
Almost surely, 2132251333231551 is an apocalyptic number.
132251333231551 is a deficient number, since it is larger than the sum of its proper divisors (1).
132251333231551 is an equidigital number, since it uses as much as digits as its factorization.
132251333231551 is an evil number, because the sum of its binary digits is even.
The product of its digits is 243000, while the sum is 40.
Adding to 132251333231551 its reverse (155132333152231), we get a palindrome (287383666383782).
The spelling of 132251333231551 in words is "one hundred thirty-two trillion, two hundred fifty-one billion, three hundred thirty-three million, two hundred thirty-one thousand, five hundred fifty-one".
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