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132251355265457 is a prime number
BaseRepresentation
bin11110000100100000101011…
…000011010011100110110001
3122100021002212100010121120002
4132010200223003103212301
5114313301233421443312
61145135233414355345
736566562604544531
oct3604405303234661
9570232770117502
10132251355265457
113915953729725a
12129bb24735bb55
1358a43318c335c
142492ddd4494c1
15104526434a4c2
hex78482b0d39b1

132251355265457 has 2 divisors, whose sum is σ = 132251355265458. Its totient is φ = 132251355265456.

The previous prime is 132251355265399. The next prime is 132251355265459. The reversal of 132251355265457 is 754562553152231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 112507409516401 + 19743945749056 = 10606951^2 + 4443416^2 .

It is an emirp because it is prime and its reverse (754562553152231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 132251355265457 - 210 = 132251355264433 is a prime.

Together with 132251355265459, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (132251355265459) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66125677632728 + 66125677632729.

It is an arithmetic number, because the mean of its divisors is an integer number (66125677632729).

Almost surely, 2132251355265457 is an apocalyptic number.

It is an amenable number.

132251355265457 is a deficient number, since it is larger than the sum of its proper divisors (1).

132251355265457 is an equidigital number, since it uses as much as digits as its factorization.

132251355265457 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 37800000, while the sum is 56.

The spelling of 132251355265457 in words is "one hundred thirty-two trillion, two hundred fifty-one billion, three hundred fifty-five million, two hundred sixty-five thousand, four hundred fifty-seven".