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132251513256353 is a prime number
BaseRepresentation
bin11110000100100000110100…
…011101111111100110100001
3122100021010021100102101022202
4132010200310131333212201
5114313302044343200403
61145135301220542545
736566566533465431
oct3604406435774641
9570233240371282
10132251513256353
1139159608497147
12129bb290251a55
1358a435855c4aa
1424930164142c1
151045273157688
hex78483477f9a1

132251513256353 has 2 divisors, whose sum is σ = 132251513256354. Its totient is φ = 132251513256352.

The previous prime is 132251513256281. The next prime is 132251513256361. The reversal of 132251513256353 is 353652315152231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 76741682214289 + 55509831042064 = 8760233^2 + 7450492^2 .

It is a cyclic number.

It is not a de Polignac number, because 132251513256353 - 28 = 132251513256097 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 132251513256298 and 132251513256307.

It is not a weakly prime, because it can be changed into another prime (132251513246353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66125756628176 + 66125756628177.

It is an arithmetic number, because the mean of its divisors is an integer number (66125756628177).

Almost surely, 2132251513256353 is an apocalyptic number.

It is an amenable number.

132251513256353 is a deficient number, since it is larger than the sum of its proper divisors (1).

132251513256353 is an equidigital number, since it uses as much as digits as its factorization.

132251513256353 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2430000, while the sum is 47.

The spelling of 132251513256353 in words is "one hundred thirty-two trillion, two hundred fifty-one billion, five hundred thirteen million, two hundred fifty-six thousand, three hundred fifty-three".