Base | Representation |
---|---|
bin | 11110000100100001011010… |
… | …110001111110111010010100 |
3 | 122100021011221010220200211210 |
4 | 132010201122301332322110 |
5 | 114313304403420434422 |
6 | 1145135445101501420 |
7 | 36566621500126032 |
oct | 3604413261767224 |
9 | 570234833820753 |
10 | 132252156030612 |
11 | 391599082aaa42 |
12 | 129bb42b571870 |
13 | 58a442b7835a7 |
14 | 2493077933552 |
15 | 10452ae7c410c |
hex | 78485ac7ee94 |
132252156030612 has 48 divisors (see below), whose sum is σ = 327056923936512. Its totient is φ = 41450707000320.
The previous prime is 132252156030479. The next prime is 132252156030727. The reversal of 132252156030612 is 216030651252231.
132252156030612 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 313581564 + ... + 314003027.
It is an arithmetic number, because the mean of its divisors is an integer number (6813685915344).
Almost surely, 2132252156030612 is an apocalyptic number.
132252156030612 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
132252156030612 is an abundant number, since it is smaller than the sum of its proper divisors (194804767905900).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132252156030612 is a wasteful number, since it uses less digits than its factorization.
132252156030612 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 627585648 (or 627585646 counting only the distinct ones).
The product of its (nonzero) digits is 129600, while the sum is 39.
The spelling of 132252156030612 in words is "one hundred thirty-two trillion, two hundred fifty-two billion, one hundred fifty-six million, thirty thousand, six hundred twelve".
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