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132254010431541 = 32294112359032841
BaseRepresentation
bin11110000100100011001001…
…010011111101100000110101
3122100021100201101022000200200
4132010203021103331200311
5114313322203132302131
61145140353104031113
736600015445230525
oct3604431123754065
9570240641260620
10132254010431541
113915a67a040899
12129bb868602499
1358a4665a0cc4b
1424931b1d2b685
15104536c4c62e6
hex7848c94fd835

132254010431541 has 24 divisors (see below), whose sum is σ = 202440957951960. Its totient is φ = 83052700684800.

The previous prime is 132254010431507. The next prime is 132254010431581. The reversal of 132254010431541 is 145134010452231.

132254010431541 is a `hidden beast` number, since 1 + 3 + 2 + 2 + 5 + 4 + 0 + 104 + 3 + 1 + 541 = 666.

It can be written as a sum of positive squares in 4 ways, for example, as 3235875713316 + 129018134718225 = 1798854^2 + 11358615^2 .

It is not a de Polignac number, because 132254010431541 - 29 = 132254010431029 is a prime.

It is a super-2 number, since 2×1322540104315412 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 132254010431496 and 132254010431505.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132254010431581) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 6179505720 + ... + 6179527121.

It is an arithmetic number, because the mean of its divisors is an integer number (8435039914665).

Almost surely, 2132254010431541 is an apocalyptic number.

It is an amenable number.

132254010431541 is a deficient number, since it is larger than the sum of its proper divisors (70186947520419).

132254010431541 is a wasteful number, since it uses less digits than its factorization.

132254010431541 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12359032917 (or 12359032914 counting only the distinct ones).

The product of its (nonzero) digits is 57600, while the sum is 36.

Adding to 132254010431541 its reverse (145134010452231), we get a palindrome (277388020883772).

The spelling of 132254010431541 in words is "one hundred thirty-two trillion, two hundred fifty-four billion, ten million, four hundred thirty-one thousand, five hundred forty-one".

Divisors: 1 3 9 29 41 87 123 261 369 1189 3567 10701 12359032841 37077098523 111231295569 358411952389 506720346481 1075235857167 1520161039443 3225707571501 4560483118329 14694890047949 44084670143847 132254010431541