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132254146654601 is a prime number
BaseRepresentation
bin11110000100100011010001…
…011011100111000110001001
3122100021101001212121212121012
4132010203101123213012021
5114313322443020421401
61145140414411453305
736600022021140356
oct3604432133470611
9570241055555535
10132254146654601
113915a739a23234
12129bb8a6157235
1358a4687cc70ca
1424931c606b62d
1510453794338bb
hex7848d16e7189

132254146654601 has 2 divisors, whose sum is σ = 132254146654602. Its totient is φ = 132254146654600.

The previous prime is 132254146654529. The next prime is 132254146654733. The reversal of 132254146654601 is 106456641452231.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 128196198285376 + 4057948369225 = 11322376^2 + 2014435^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132254146654601 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 132254146654601.

It is not a weakly prime, because it can be changed into another prime (132254146654001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66127073327300 + 66127073327301.

It is an arithmetic number, because the mean of its divisors is an integer number (66127073327301).

Almost surely, 2132254146654601 is an apocalyptic number.

It is an amenable number.

132254146654601 is a deficient number, since it is larger than the sum of its proper divisors (1).

132254146654601 is an equidigital number, since it uses as much as digits as its factorization.

132254146654601 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4147200, while the sum is 50.

The spelling of 132254146654601 in words is "one hundred thirty-two trillion, two hundred fifty-four billion, one hundred forty-six million, six hundred fifty-four thousand, six hundred one".