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132254331063512 = 23728317925190473
BaseRepresentation
bin11110000100100011011100…
…011011000100110011011000
3122100021101112201121211001212
4132010203130123010303120
5114313323332223013022
61145140445000202252
736600026420450600
oct3604433433046330
9570241481554055
10132254331063512
113915a824027399
12129bb937a69388
1358a46b72829c8
142493202751c00
15104538a70d3e2
hex7848dc6c4cd8

132254331063512 has 192 divisors, whose sum is σ = 294742143964800. Its totient is φ = 55462231104000.

The previous prime is 132254331063497. The next prime is 132254331063523. The reversal of 132254331063512 is 215360133452231.

It is a self number, because there is not a number n which added to its sum of digits gives 132254331063512.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1461764708 + ... + 1461855180.

It is an arithmetic number, because the mean of its divisors is an integer number (1535115333150).

Almost surely, 2132254331063512 is an apocalyptic number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 132254331063512, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (147371071982400).

132254331063512 is an abundant number, since it is smaller than the sum of its proper divisors (162487812901288).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

132254331063512 is a wasteful number, since it uses less digits than its factorization.

132254331063512 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 91006 (or 90995 counting only the distinct ones).

The product of its (nonzero) digits is 388800, while the sum is 41.

The spelling of 132254331063512 in words is "one hundred thirty-two trillion, two hundred fifty-four billion, three hundred thirty-one million, sixty-three thousand, five hundred twelve".