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13226572810433 is a prime number
BaseRepresentation
bin1100000001111000110100…
…1011001000100011000001
31201211110002121012211220002
43000132031023020203001
53213201010114413213
644044111554125345
72533405542615053
oct300361513104301
951743077184802
1013226572810433
11423a3a3598754
121597494580855
1374c350316b58
1433a2533078d3
1517e0c090b658
hexc078d2c88c1

13226572810433 has 2 divisors, whose sum is σ = 13226572810434. Its totient is φ = 13226572810432.

The previous prime is 13226572810421. The next prime is 13226572810469. The reversal of 13226572810433 is 33401827562231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7308679750849 + 5917893059584 = 2703457^2 + 2432672^2 .

It is a cyclic number.

It is not a de Polignac number, because 13226572810433 - 28 = 13226572810177 is a prime.

It is not a weakly prime, because it can be changed into another prime (13226572810133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6613286405216 + 6613286405217.

It is an arithmetic number, because the mean of its divisors is an integer number (6613286405217).

Almost surely, 213226572810433 is an apocalyptic number.

It is an amenable number.

13226572810433 is a deficient number, since it is larger than the sum of its proper divisors (1).

13226572810433 is an equidigital number, since it uses as much as digits as its factorization.

13226572810433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1451520, while the sum is 47.

The spelling of 13226572810433 in words is "thirteen trillion, two hundred twenty-six billion, five hundred seventy-two million, eight hundred ten thousand, four hundred thirty-three".