Base | Representation |
---|---|
bin | 111101100101111100… |
… | …1000001110101001001 |
3 | 110122102002212011021102 |
4 | 1323023321001311021 |
5 | 4131342023242213 |
6 | 140432555351145 |
7 | 12361524161102 |
oct | 1731371016511 |
9 | 418362764242 |
10 | 132269743433 |
11 | 51105904a53 |
12 | 21774a524b5 |
13 | c61c1b4c99 |
14 | 658aadd3a9 |
15 | 369225a158 |
hex | 1ecbe41d49 |
132269743433 has 2 divisors, whose sum is σ = 132269743434. Its totient is φ = 132269743432.
The previous prime is 132269743381. The next prime is 132269743483. The reversal of 132269743433 is 334347962231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 97901403664 + 34368339769 = 312892^2 + 185387^2 .
It is a cyclic number.
It is not a de Polignac number, because 132269743433 - 214 = 132269727049 is a prime.
It is not a weakly prime, because it can be changed into another prime (132269743483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66134871716 + 66134871717.
It is an arithmetic number, because the mean of its divisors is an integer number (66134871717).
Almost surely, 2132269743433 is an apocalyptic number.
It is an amenable number.
132269743433 is a deficient number, since it is larger than the sum of its proper divisors (1).
132269743433 is an equidigital number, since it uses as much as digits as its factorization.
132269743433 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1959552, while the sum is 47.
The spelling of 132269743433 in words is "one hundred thirty-two billion, two hundred sixty-nine million, seven hundred forty-three thousand, four hundred thirty-three".
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