Base | Representation |
---|---|
bin | 10011010000001000111… |
… | …100011101101010011111 |
3 | 11200110220010220021000021 |
4 | 103100020330131222133 |
5 | 133134000444320124 |
6 | 2451440001213011 |
7 | 164404113260452 |
oct | 23201074355237 |
9 | 4613803807007 |
10 | 1322999995039 |
11 | 470099008958 |
12 | 1944a6031167 |
13 | 979b2184268 |
14 | 48068075499 |
15 | 246332337e4 |
hex | 13408f1da9f |
1322999995039 has 2 divisors, whose sum is σ = 1322999995040. Its totient is φ = 1322999995038.
The previous prime is 1322999995013. The next prime is 1322999995069. The reversal of 1322999995039 is 9305999992231.
It is a weak prime.
It is an emirp because it is prime and its reverse (9305999992231) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1322999995039 is a prime.
It is a super-2 number, since 2×13229999950392 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1322999995069) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661499997519 + 661499997520.
It is an arithmetic number, because the mean of its divisors is an integer number (661499997520).
Almost surely, 21322999995039 is an apocalyptic number.
1322999995039 is a deficient number, since it is larger than the sum of its proper divisors (1).
1322999995039 is an equidigital number, since it uses as much as digits as its factorization.
1322999995039 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 95659380, while the sum is 70.
The spelling of 1322999995039 in words is "one trillion, three hundred twenty-two billion, nine hundred ninety-nine million, nine hundred ninety-five thousand, thirty-nine".
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