1323000050335 has 4 divisors (see below), whose sum is σ = 1587600060408. Its totient is φ = 1058400040264.

The previous prime is 1323000050321. The next prime is 1323000050347. The reversal of 1323000050335 is 5330500003231.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1323000050335 - 2⁵ = 1323000050303 is a prime.

It is a super-2 number, since 2×1323000050335² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 132300005029 + ... + 132300005038.

It is an arithmetic number, because the mean of its divisors is an integer number (396900015102).

Almost surely, 2^{1323000050335} is an apocalyptic number.

1323000050335 is a deficient number, since it is larger than the sum of its proper divisors (264600010073).

1323000050335 is an equidigital number, since it uses as much as digits as its factorization.

1323000050335 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 264600010072.

The product of its (nonzero) digits is 4050, while the sum is 25.

Adding to 1323000050335 its reverse (5330500003231), we get a palindrome (6653500053566).

The spelling of 1323000050335 in words is "one trillion, three hundred twenty-three billion, fifty thousand, three hundred thirty-five".