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13230001213001 is a prime number
BaseRepresentation
bin1100000010000101100110…
…0001011100111001001001
31201211202221112100202001222
43000201121201130321021
53213230020302304001
644045440104451425
72533556522555606
oct300413141347111
951752845322058
1013230001213001
1142408a2863301
121598090779b75
1374c7786a5821
1433a49a7896ad
1517e2218c461b
hexc085985ce49

13230001213001 has 2 divisors, whose sum is σ = 13230001213002. Its totient is φ = 13230001213000.

The previous prime is 13230001212983. The next prime is 13230001213003. The reversal of 13230001213001 is 10031210003231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7823209000000 + 5406792213001 = 2797000^2 + 2325251^2 .

It is a cyclic number.

It is not a de Polignac number, because 13230001213001 - 214 = 13230001196617 is a prime.

It is a super-3 number, since 3×132300012130013 (a number of 40 digits) contains 333 as substring.

Together with 13230001213003, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13230001213003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6615000606500 + 6615000606501.

It is an arithmetic number, because the mean of its divisors is an integer number (6615000606501).

Almost surely, 213230001213001 is an apocalyptic number.

It is an amenable number.

13230001213001 is a deficient number, since it is larger than the sum of its proper divisors (1).

13230001213001 is an equidigital number, since it uses as much as digits as its factorization.

13230001213001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 13230001213001 its reverse (10031210003231), we get a palindrome (23261211216232).

The spelling of 13230001213001 in words is "thirteen trillion, two hundred thirty billion, one million, two hundred thirteen thousand, one".